Question

bài 1: Tính bằng cách hợp lí

1)\(\frac{11}{3}:3\frac{1}{3}-3\)

2)\(\frac{5}{6}:\frac{3}{52}-\frac{5}{6}.47\frac{1}{3}\)

3)\(\left(9\frac{3}{4}:\frac{26}{5}+\frac{17}{5}.2\frac{7}{34}\right):\left(-1\frac{9}{16}\right)\)

4)\(\left(\frac{1}{2}-1\right).\left(\frac{1}{3}-1\right)...\left(\frac{1}{2002}-1\right).\left(\frac{1}{2003}-1\right)\)

5)\(\left(1-\frac{1}{21}\right).\left(1-\frac{1}{28}\right).\left(1-\frac{1}{36}\right)...\left(1-\frac{1}{1326}\right)\)

bài 2: tìm x :

1)\(\left(\frac{2x}{3}-3\right):\left(-10\right)=\frac{2}{5}\)

2)\(\left(x+\frac{1}{5}\right)\left(x-\frac{2}{7}\right)< 0\)

mách mình với mấy cái kia là hỗn số nha

 

Answer 1

Bài 1:

1) \(\frac{11}{3}\): 3\(\frac{1}{3}\)- 3

= \(\frac{11}{3}\): \(\frac{10}{3}\)- 3

= \(\frac{11}{3}\). \(\frac{3}{10}\)- 3 

= \(\frac{11}{10}\)- 3

= \(\frac{-19}{10}\)

2) \(\frac{5}{6}\):  \(\frac{3}{52}\) - \(\frac{5}{6}\). 47\(\frac{1}{3}\)

= \(\frac{5}{6}\) . \(\frac{52}{3}\)- \(\frac{5}{6}\). 47\(\frac{1}{3}\)

= \(\frac{5}{6}\).(\(\frac{52}{3}\)- 47\(\frac{1}{3}\))

= \(\frac{5}{6}\).( -30)

= -25

Answer 2

mách mình mấy câu kia với