\(\frac{x}{3}=\frac{5}{15}\)
\(\Leftrightarrow\frac{x}{3}=\frac{1}{3}\)
\(\Rightarrow x=1\)
\(\frac{x}{3}=\frac{15}{5}\)
\(\rightarrow\frac{x}{3}=\frac{1}{3}\)
\(x=1\)
\(\frac{x}{2}=\frac{8}{x}\)
\(x^2=2\times8\)
\(x^2=16\)
\(x^2=4^2\)
\(\Leftrightarrow x=4\)
\(\frac{y}{-7}=\frac{-9}{21}\)
\(\frac{y}{-7}=\frac{-3}{7}\)
\(\frac{y}{-7}=\frac{3}{-7}\)
\(\Rightarrow y=3\)
Bài làm
a)\(\frac{x}{3}=\frac{5}{15}\) b) \(\frac{x}{2}=\frac{8}{x}\) c) \(\frac{y}{-7}=-\frac{9}{21}\)
Ta có: \(\frac{5}{15}=\frac{1}{3}\) => \(x.x=8.2\) => \(y.21=-7.-9\)
Mà \(\frac{x}{3}\)và \(\frac{1}{3}\) => \(x^2=16\) => \(y.21=36\)
có cùng mẫu số. Do đó: x = 4 => \(y=36:21\)
=> x = 1 Vậy x = 4 => \(y=\frac{36}{21}\)
Vậy x =1 => \(y=\frac{12}{7}\)
Vậy \(y=\frac{12}{7}\)
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