Question

Bài 1: Tìm x

a) √ x+1 = 12

b)(2x)² -1 = 5

Giúp mk nhanh chìu mk đi hcj r

Answer 1

a) \(\sqrt{x+1}=12\)

\(x+1=144\)

\(x=144-1\)

\(x=143\)

b) \(2x^2-1=5\)

\(2x^2=5+1\)

\(2x^2=6\)

\(x^2=3\)

\(x=\pm\sqrt{3}\)

Answer 2

\(a,\sqrt{x+1}=12\)

\(\Rightarrow x+1=144\)

\(x=144-1\)

\(x=143\)

\(b,\left(2x\right)^2-1=5\)

\(2x^2=1+5\)

\(2x^2=6\)

\(\Rightarrow x^2=3\)

\(\Rightarrow x=\perp\sqrt{3}\)