Ta có : 2x - 20 = x + 10
=> 2x - x = 20 + 10
=> x = 30
\(2x-20=x+10\)
\(2x-x=10+20\)
\(x=30\)
\(2x-20=x+10\)
\(\Leftrightarrow2x-x=10+20\)
\(\Leftrightarrow x=30\)
#)Giải :
\(2x-20=x+10\)
\(\Leftrightarrow2x-x=20+10\)
\(\Leftrightarrow x=20+10\)
\(\Leftrightarrow x=30\)
2x- 20 = x +10
=> x = 10 + 20
=> x = 30
Vậy x = 30
\(2x-20=x+10\)
\(\Leftrightarrow2x-x=10+20\)
\(\Leftrightarrow x=30\)
Vậy...
\(2x-20=x+10\)
\(\Rightarrow2x-x=10+20\)
\(\Rightarrow x=30\)
Bài giải
\(2x-20=x+10\)
\(\Rightarrow\text{ }2x-x=20+10\)
\(x=30\)
2x - 20 = x + 10
2x - x = 20 + 10
x = 30