b) \(3^{x+1}=9^x\)
\(3^{x+1}=\left(3^2\right)^x\) c)
\(3^{x+1}=3^{2x}\)
\(\Rightarrow x+1=2x\)
\(1=2x-x\)
\(1=x\)
Vậy x=1
c) 23x+2 = 4x+5 d)32x-1 = 243
23x+2 = (22)x+5 32x-1 = 35
23x+2 = 22x+10 => 2x-1 = 5
=> 3x+2 = 2x + 10 2x = 6
3x - 2x = 10-2 x=3
=> x = 8