Question

Bài 1: tìm x

 \(33^{2x}:11^{2x}=81\)

\(\frac{x}{-5}=\frac{4}{21}\)

Bài 2: rút gọn:

\(A=\frac{1+3^4+4^8+3^{12}}{1+3^2+3^4+3^6+3^8+3^{10}+3^{12}+3^{14}}\)

 

Answer 1

Bài 1: 

a) \(33^{2x}:11^{2x}=81\)\(\Leftrightarrow\left(33:11\right)^{2x}=81\)

\(\Leftrightarrow3^{2x}=3^4\)\(\Leftrightarrow2x=4\)\(\Leftrightarrow x=2\)

Vậy \(x=2\)

b) \(\frac{x}{-5}=\frac{4}{21}\)\(\Leftrightarrow21x=-20\)\(\Leftrightarrow x=\frac{-20}{21}\)

Vậy \(x=\frac{-20}{21}\)

Bài 2:

\(A=\frac{1+3^4+3^8+3^{12}}{1+3^2+3^4+3^6+3^8+3^{10}+3^{12}+3^{14}}\)

\(=\frac{1+3^4+3^8+3^{12}}{\left(1+3^4+3^8+3^{12}\right)+\left(3^2+3^6+3^{10}+3^{14}\right)}\)

\(=\frac{1+3^4+3^8+3^{12}}{\left(1+3^4+3^8+3^{12}\right)+3^2.\left(1+3^4+3^8+3^{12}\right)}\)

\(=\frac{1+3^4+3^8+3^{12}}{\left(1+3^4+3^8+3^{12}\right).\left(1+3^2\right)}=\frac{1}{1+3^2}=\frac{1}{1+9}=\frac{1}{10}\)

Answer 2

\(33^{2x}:11^{2x}=81\)!

\(\left(33:11\right)^{2x}=81\)

\(3^{2x}=81\)

\(3^{2x}=3^4\)

\(2x=4\)

\(x=4:2\)

\(x=2\)

vậy \(x=2\)

\(\frac{x}{-5}=\frac{4}{21}\)

x.21=-5.4

x.21=-20

x=-20:21

\(x=-\frac{20}{21}\)

vậy \(x=-\frac{20}{21}\)