Question

bài 1: tìm số tự nhiên x, biết:

a)83-6.(x-7)=35

b)246+7.(x+15)=442

c)303:{606:[450-(x.4³-8³.2)]}=101

d)(196-23.x).3²⁰²⁵=3²⁰²⁹

giúp mình làm với, mình cần gấp, cảm ơn, ai nhanh nhất mình sẽ tick!!!!

 

Answer 1

a)83-6.(x-7)=35

6(x-7)=83-35=48

x-7=48:6=8

x=8+7=15

b)246+7.(x+15)=442

7(x+15)=442-246=196

x+15=196:7=28

x=28-15=13

Answer 2

c)303:{606:[450-(x.4³-8³.2)]}=101

606:[450-(x.4³-8³.2)]=303:101=3

450-(x.4³-8³.2)=606:3=202

x . 64-512=450-202=248

x . 64=248+512=760

x=760:64=11,875

Answer 3

tks cho mk nhe

Answer 4

\(d,\left[196-23\cdot x\right]\cdot3^{2025}=3^{2029}\)

\(\Leftrightarrow\left[196-23\cdot x\right]=3^{2029}:3^{2025}=3^4=81\)

\(\Leftrightarrow196-23\cdot x=81\)

\(\Leftrightarrow23\cdot x=115\Leftrightarrow x=5\)