a) \(\left[\frac{1}{3}\right]^{50}.\left(-9\right)^{25}-\frac{2}{3}:4\)
\(\Rightarrow\frac{1}{3^{50}}.\left(-9\right)^{25}-\frac{2}{3}.\frac{1}{4}\)
\(\Rightarrow\frac{\left(-9\right)}{9^{25}}-\frac{1}{6}\)
\(\Rightarrow1-\frac{1}{6}\)
\(\Rightarrow\frac{6}{6}-\frac{1}{6}=\frac{5}{6}\)
Vậy = 5/6
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