Ta có:
\(A=\frac{3.5.7.11.13.37-10101}{1212120+40404}\)
\(=\frac{\left(3.7.11.13.37\right).5-10101.1}{120.10101+4.10101}\)
\(=\frac{10101.\left(5-1\right)}{10101.\left(120+4\right)}\)
\(=\frac{4}{124}=\frac{1}{31}\)
Sai rồi:
A = 5.11.(3.7.13.37) - 10101/(10101.120 + 10101.4)
= (5.11.10101 - 10101)/(10101.120+10101.4)
= 10101(5.11-1)/10101(120+4)
= 27/62.
A= 5.11.(3.7.13.37)-10101/(10101.120+10101.4)
=(5.11.10101-10101)/(10101.120+10101.4)
=10101.(5.11-1)/10101(120+4)
=27/62
k mik nha mik k lại 100 cái lun
A=5.11.(3.7.13.37)-10101/120.10101+4.10101
A=55.10101-10101/10101.(124+4)
A=10101.(55-1)/10101.124
A=1.54/1.124
A=54/124
A=27/62