Question

 

Bài 1: Phân tích đa thức thành nhân tử

 

a) x^2 - x - xy - 2y^2 + 2y

 

b) x^2 + 4xy + 2x + 3y^2 + 6y

 

Answer 1

a) \(x^2-x-xy-2y^2+2y\)

\(=x^2-x-2xy+xy-2y^2+2y\)

\(=\left(-2y^2-2xy+2y\right)+\left(xy+x^2-x\right)\)

\(=2y\left(-y-x+1\right)+x\left(y+x-1\right)\)

\(=-2y\left(y+x-1\right)+x\left(y+x-1\right)\)

\(=\left(x-2y\right)\left(y+x-1\right)\)

Answer 2

b) \(x^2+4xy+2x+3y^2+6y\)

\(=x^2+3xy+xy+2x+3y^2+6y\)

\(=\left(3y^2+3xy+6y\right)+\left(xy+x^2+2x\right)\)

\(=3y\left(y+x+2\right)+x\left(y+x+2\right)\)

\(=\left(3y+x\right)\left(y+x+2\right)\)