`1)f(x)=-2x^2+5x+1`
`<=>f(x)=-2(x^2-5/2x-1/2)`
`<=>f(x)=-2(x^2-2x. 5/4+25/16-33/16)`
`<=>f(x)=-2(x-5/4)^2+33/8`
Vì `-2(x-5/4)^2 <= 0 AA x`
`<=>-2(x-5/4)^2+33/8 <= 33/8 AA x`
Hay `f(x) <= 33/8 AA x`
Dấu "`=`" xảy ra `<=>(x-5/4)^2=0<=>x=5/4`
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`2)f(x)=3x^2-7x+1`
`<=>f(x)=3(x^2-7/3x+1/3)`
`<=>f(x)=3(x^2-2x. 7/6+49/36-37/36)`
`<=>f(x)=3(x-7/6)^2-37/12`
Vì `3(x-7/6)^2 >= 0 AA x`
`<=>3(x-7/6)^2-37/12 >= -37/12 AA x`
Hay `f(x) >= -37/12 AA x`
Dấu "`=`" xảy ra `<=>(x-7/6)^2=0<=>x=7/6`