Question

bài 1 

a, \(\left(x+\frac{5}{3}\right).\left(x-\frac{5}{4}\right)=0\)

giúp mik với !!!

 

Answer 1

\(a,\left(x+\frac{5}{3}\right).\left(x-\frac{5}{4}\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x+\frac{5}{3}=0\\x-\frac{5}{4}=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{-5}{3}\\x=\frac{5}{4}\end{cases}}\)

Vậy \(x=\frac{-5}{3}\)hoặc \(x=\frac{5}{4}\).

Học tốt

Answer 2

\(\left(x+\frac{5}{3}\right)\left(x-\frac{5}{4}\right)=0\)

<=> x + 5/3 = 0 hoặc x - 5/4 = 0

<=> x = - 5/3 hoặc x = 5/4

Answer 3

\(\left(x+\frac{5}{3}\right)\left(x-\frac{5}{4}\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x+\frac{5}{3}=0\\x-\frac{5}{4}=0\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=0-\frac{5}{3}\\x=0+\frac{5}{4}\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=\frac{-5}{3}\\x=\frac{5}{4}\end{cases}}\)

Answer 4

(x+5/3).(x-5/4)=0

x+5/3=0   hoặc   x-5/4=0

x=0-5/3    hoặc   x=0+5/4

x=-5/3   hoặc     x=5/4

vậy x=-5/3   hoặc   x=5/4

Answer 5

\(\left(x+\frac{5}{3}\right)\left(x-\frac{5}{4}\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x+\frac{5}{3}=0\\x-\frac{5}{4}=0\end{cases}\Rightarrow\orbr{\begin{cases}x=-\frac{5}{3}\\x=\frac{5}{4}\end{cases}}}\)

Vậy ...........

Answer 6

Bài làm 

\(\left(x+\frac{5}{3}\right)\left(x-\frac{5}{4}\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x=-\frac{5}{3}\\x=\frac{5}{4}\end{cases}}\)TM

Answer 7

\(\left(x+\frac{5}{3}\right).\left(x-\frac{5}{4}\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x+\frac{5}{3}=0\\x-\frac{5}{4}=0\end{cases}\Rightarrow\orbr{\begin{cases}x=0-\frac{5}{3}\\x=0+\frac{5}{4}\end{cases}\Rightarrow}\orbr{\begin{cases}x=-\frac{5}{3}\\x=\frac{5}{4}\end{cases}}}\)

Vậy \(x\in\left\{-\frac{5}{3};\frac{5}{4}\right\}\)

Answer 8

\(\left(x+\frac{5}{3}\right)\left(x-\frac{5}{4}\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x+\frac{5}{3}=0\\x-\frac{5}{4}=0\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=-\frac{5}{3}\\x=\frac{5}{4}\end{cases}}\)