Question

bài 1 

A = 2¹⁰ .13 + 2¹⁰ .65 trên 2⁸ .104 

B= ( 1 +2 +3 + ... + 100 ) . ( 1² + 2² + 3² + ... + 100² ) . (65 .111 - 13 .15 . 37 ) 

bài 2 

( x +1 ) + ( x +2 ) + ( x +3 ) + ... + ( x + 100 ) = 5750 

ai giúp mik đâu tiền mik sẽ tik cho người ấy 

các bn giúp mik nha mik đang cần gấp 

 

 

Answer 1

Bài 1:

\(A=\frac{2^{10}.13+2^{10}.65}{2^8.104}=\frac{2^{10}.13+2^{10}.13.5}{2^8.2^2.13.2}\) 

 \(=\frac{2^{10}.13\left(1+5\right)}{2^{10}.13.2}=\frac{2^{10}.13.6}{2^{10}.13.2}=\frac{6}{2}=3\)

\(B=\left(1+2+3+...+100\right)\left(1^2+2^2+3^2+...+100^2\right)\left(65.111-13.15.37\right)\)

\(=\left(1+2+3+...+100\right)\left(1^2+2^2+...+100^2\right)\left(65.111-13.5.3.37\right)\)

\(=\left(1+2+...+100\right)\left(1^2+2^2+...+100^2\right)\left(65.111-65.111\right)\)

\(=\left(1+2+...+100\right)\left(1^2+2^2+...+100^2\right).0\)

\(=0\)

Bài 2: 

\(\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+...+\left(x+100\right)=5750\) 

\(x+1+x+2+x+3+...+x+100=5750\)

\(x+x+x+...+x+1+2+3+...+100=5750\)

\(100x+5050=5750\)

\(100x=5750-5050\)

\(100x=700\)

\(x=700:100\)

\(x=7\)

t_i_c_k cho mình nha ^^

Answer 2

ban kia lam dung roi do 

k tui nha

thanks