\(\text{Đặt số táo lúc đầu là a}\)
\(\text{Theo bài ra, ta có: }\)
\(\left(a-\frac{1}{3}a-1\right)-\left[\frac{1}{3}\left(a-\frac{1}{3}-1\right)-1\right]-49=0\)
\(\Rightarrow\left(\frac{2}{3}a-1\right)-\left[\frac{1}{3}\left(\frac{2}{3}a-1\right)+1\right]-49=0\)
\(\Rightarrow\frac{2}{3}a-1-\left[\frac{2}{9}a-\frac{1}{3}+1\right]-49=0\)
\(\Rightarrow\frac{2}{3}a-1-\frac{2}{9}a+\frac{1}{3}-1-49=0\)
\(\Rightarrow\left(\frac{2}{3}-\frac{2}{9}\right).a-51+\frac{1}{3}=0\)
\(\Rightarrow\frac{4}{9}a=51-\frac{1}{3}\)
\(\Rightarrow\frac{4}{9}a=\frac{152}{3}\)
\(\Rightarrow a=\frac{152}{3}:\frac{4}{9}\)
\(\Rightarrow a=\frac{152.9}{3.4}=114\left(\text{quả}\right)\)
\(\text{Vậy ...}\)