Question

B=1/3+1/15+1/35+...+1/1089

giúp gải bài toán này với 

Answer 1

HÌnh như đề sai

Answer 2

Đề sai rồi Sửa lại thành \(\dfrac{1}{3}+\dfrac{1}{15}+\dfrac{1}{35}+...+\dfrac{1}{1023}\) nha

\(\dfrac{1}{3}+\dfrac{1}{15}+\dfrac{1}{35}+...+\dfrac{1}{1023}\)

B = \(\dfrac{1}{1\cdot3}+\dfrac{1}{3\cdot5}+\dfrac{1}{5\cdot7}+...+\dfrac{1}{31\cdot33}\)

B = \(1-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{31}+\dfrac{1}{31}-\dfrac{1}{33}\)

B = \(1-\dfrac{1}{33}\)

B = \(\dfrac{32}{33}\)

Answer 3

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