Ta có\(B=13!-11!\)
\(B=\left(1.2.3.....11\right).12.13-\left(1.2.3....11\right)\)
\(B=\left(1.2.3.4.5.6.7.8.9.10.11\right)\left(12.13-1\right)\)
\(B=\left(5.11\right)\left(1.2.3.4.6.7.8.9.10\right).155\)
\(B=55.155.\left(1.2.3.4.6.7.8.9.10\right)⋮55\)
Vậy\(B⋮55\)