\(B=\frac{1}{25.27}+\frac{1}{27.29}+\frac{1}{29.31}+...+\frac{1}{73.75}\)
\(B=\frac{1}{2}\left(\frac{1}{25}-\frac{1}{27}+\frac{1}{27}-\frac{1}{29}+\frac{1}{29}-\frac{1}{31}+...+\frac{1}{73}-\frac{1}{75}\right)\)
\(B=\frac{1}{2}\left(\frac{1}{25}-\frac{1}{75}\right)\)
\(B=\frac{1}{2}\cdot\frac{2}{75}\)
\(B=\frac{1}{75}\)
\(B=\frac{1}{25.27}+\frac{1}{27.29}+\frac{1}{29.31}+....+\frac{1}{73.75}\)
\(B=\frac{1}{2}.\left(\frac{1}{25}-\frac{1}{27}+\frac{1}{27}-\frac{1}{29}+\frac{1}{29}-\frac{1}{31}+...+\frac{1}{73}-\frac{1}{75}\right)\)
\(B=\frac{1}{2}\cdot\left(\frac{1}{25}-\frac{1}{75}\right)\)
\(B=\frac{1}{2}\cdot\frac{2}{75}=\frac{1}{75}\)
Theo đề bài ta có:
\(B=\frac{1}{25.27}+\frac{1}{27.29}+\frac{1}{29.31}+...+\frac{1}{73.75}\)
\(\Leftrightarrow B=\frac{1}{2}.\left(\frac{1}{25}-\frac{1}{27}+\frac{1}{27}-\frac{1}{29}+...+\frac{1}{73}-\frac{1}{75}\right)\)
\(\Leftrightarrow B=\frac{1}{2}.\left(\frac{1}{25}-\frac{1}{27}\right)\)
\(\Leftrightarrow B=\frac{1}{2}\cdot\frac{2}{75}\)
\(\Leftrightarrow B=\frac{1}{75}\)
B = 1/25x27 + 1/27x29 +...+ 1/73x75
2B = 2/25x27 +2/27x29 +...+ 2/73x75
= 1/25 - 1/27 + 1/27 - 1/29 +...+ 1/73 - 1/75
= 1/25 - 1/75
= 2/75
B = 2/75 : 2
= 1/75
