x13 = 27.x16
=> x13 - 27x16 = 0
=> x13(1 - 27x3) = 0
=> \(\orbr{\begin{cases}x^{13}=0\\1-27x^3=0\end{cases}}\)
=> \(\orbr{\begin{cases}x=0\\27x^3=1\end{cases}}\)
=> \(\orbr{\begin{cases}x=0\\x^3=\frac{1}{27}\end{cases}}\)
=> \(\orbr{\begin{cases}x=0\\x=\frac{1}{3}\end{cases}}\)
c) \(\left(\frac{1}{2}\right)^{2x-1}=\frac{1}{8}\)
=> \(\left(\frac{1}{2}\right)^{2x-1}=\left(\frac{1}{2}\right)^3\)
=> \(2x-1=3\)
=> \(2x=3+1\)
=> \(2x=4\)
=> \(x=4:2=2\)
\(b,\text{ }x^{13}=27\cdot x^{16}\)
\(x^{16}\text{ : }x^{13}=27\)
\(x^3=3^3\)
\(x=3\)
\(b,\text{ }x^{13}=27\cdot x^{16}\)
\(x^{16}\text{ : }x^{13}=27\)
\(x^3=3^3\)
\(x=3\)
\(c,\text{ }\left(\frac{1}{2}\right)^{2x-1}=\frac{1}{8}\)
\(\left(\frac{1}{2}\right)^{2x-1}=\left(\frac{1}{2}\right)^3\)
\(2x-1=3\)
\(2x=3+1\)
\(2x=4\)
\(x=4\text{ : }2\)
\(x=2\)
\(c,\text{ }\left(\frac{1}{2}\right)^{2x-1}=\frac{1}{8}\)
\(\left(\frac{1}{2}\right)^{2x-1}=\left(\frac{1}{2}\right)^3\)
\(2x-1=3\)
\(2x=3+1\)
\(2x=4\)
\(x=4\text{ : }2\)
\(x=2\)
b)x13=27.x16
x16:x13=27
x3=33
x=3
vậy x=3
c)(1/2)2x-1=1/8
(1/2)2x-1=(1/2)3
2x-1=3
2x=3+1
2x=4
x=4:2
x=2
vậy x=2