Question

B=( \(\frac{5}{2\cdot4}\)+ \(\frac{5}{4\cdot6}\)+ ....... +\(\frac{5}{100\cdot102}\))

Answer 1

\(B=\frac{5}{2.4}+\frac{5}{4.6}+...+\frac{5}{100.102}\)

\(B=\frac{5}{2}.\left(\frac{1}{2}-\frac{1}{4}\right)+\frac{5}{2}.\left(\frac{1}{4}-\frac{1}{6}\right)+...+\frac{5}{2}.\left(\frac{1}{100}-\frac{1}{102}\right)\)

\(B=\frac{5}{2}.\left(\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+...+\frac{1}{100}-\frac{1}{102}\right)\)

\(B=\frac{5}{2}.\left(\frac{1}{2}-\frac{1}{102}\right)\)

\(B=\frac{5}{2}.\frac{25}{51}\)

\(B=\frac{125}{102}\)

Answer 2

đè là gì vậy cho mỗi phép tính để đấy à coi để người khác nghĩ đề à