kkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkk100
Đúng 0
Bình luận (0)
Các câu hỏi tương tự
B = \(\frac{8}{9}+\frac{24}{25}+\frac{48}{49}+...+\frac{200\cdot202}{201^2}\)
Chứng minh B > 99,75.
Cho B=8/9 + 24/25 + 48/49 + ... + 200.202/2012. CMR B>99,75.
Cho B = \(\frac{8}{9}+\frac{24}{25}+\frac{48}{49}+...+\frac{200.202}{201^2}\) Chứng minh B > 99,75
Cho B = \(\frac{8}{9}+\frac{24}{25}+\frac{48}{49}+.....+\frac{200.202}{201^2}\) Chứng minh : B > 99,75
cho B = \(\frac{8}{9}+\frac{24}{25}+\frac{48}{49}+....+\frac{200.202}{201^2}\)chứng minh B > 99,75
\(B=\frac{8}{9}+\frac{24}{25}+\frac{48}{49}+....+\frac{200.202}{201^2}>99,75\)
Cho B =\(\frac{8}{9}+\frac{24}{25}+\frac{48}{49}+.....\frac{200.202}{201^2}\)
CMR B >99,75
Cho \(B=\frac{8}{9}+\frac{24}{25}+\frac{48}{49}+...+\frac{200.202}{201^2}\)Chứng minh: \(B>99,75\)
Cho B = \(\frac{8}{9}\)+ \(\frac{24}{25}\)+ \(\frac{48}{49}\)+... + \(\frac{200.2002}{201^2}\). Chứng minh : B > 99,75