b) \(\frac{3\left(2x+1\right)}{4}-\frac{5x+3}{6}+\frac{x+1}{3}=\frac{x+7}{12}\)
<=> \(\frac{13\left(x+1\right)}{12}-\frac{5x+3}{6}=\frac{x+7}{12}\)
<=> 13(x + 1) - 2(5x + 3) = x + 7
<=> 13x + 13 - 10x - 6 = x + 7
<=> 3x + 7 = x + 7
<=> 3x + 7 - x = 7
<=> 2x + 7 = 7
<=> 2x = 7 - 7
<=> 2x = 0
<=> x = 0
c) 2x + 4(x - 2) = 5
<=> 2x + 4x - 8 = 5
<=> 6x - 8 = 5
<=> 6x = 5 + 8
<=> 6x = 13
<=> x = 13/6
1) 2x – (3 – 5x) = 4( x +3)
2) 5(2x-3) - 4(5x-7) =19 - 2(x+11)
3) 5x - 4(6-x)(x + 3) = (4-2x)(3-2x) + 2
4) (x - 1)3 - (3x + 2)(-12) = (x2 + 1)(x - 2) - x2
5) (3x -1)2 - (x +3)(2x-1) = 7(x + 1)(x -2) -3x
mn giúp mình vs
Thực hiện phép tính:
a.(2x^2 + 2x - 4) : (x + 2)
b. ( 2x^3 - 5x^2 - x +1 ) : (2x + 1 )
c. (x^3 - 2x + 4)/(x + 2)
d. (x^3- 3x^2): (x - 3)
e. (x^4- x- 14): (x- 2)
f. (x^4- x- 14): (x- 2)
g. (17x^2- 6x^4+ 5x^3- 23x+ 7): (7- 3x^2- 2x)
giúp mik đi ạ mik đang cần gấp T-T
1) 2x2+8x+7
2)2x2-5x-12
3)4x3-2x-4
4)x4+x+1
5)x7+x+1
m.n giúp mjk vs ạ, thanks( PTĐTTNT)
Tìm x biết:
a) (x+5).(2x+1)=0
b) x.(x+2)-3.(x+2)=0
c) 2x.(x-5)-x.(3+2x)=26
d) x2-10x-8x+16=0
e) x2-10x=25
f) 5x.(x-1)=x-1
g) 2.(x+5)-x2-5x=0
h) x2+5x-6=0
i) (2x-3)2-4.(x+1).(x-1)=49
j) x3+x2+x+1=0
k) x3-x2=4x2-8x+4
Mn ơi giúp em vs ạ,em cảm ơn trc ạ
Giải phương trình:
1> 12-2(1-x)2=3x-2=2x-3
2> 10x+3-5x=4x+12
3> 11x+42-2x=100-9x-22
4> 2x-(3-5x)=4(x+3)
5> 2(x-3)+5x(x-1)=5x2
6> -6(1,5-2x)=3(-15+2x)
7> 14x-(2x+7)=3x+(12x-13)
8> (x-4)(x+4)-2(3x-2)=(x-4)2
9> 4(x-2)-(x-3)(2x-5)
giải giúp mik với ạ
1. Rút Gọn
a) -5x (x-3).(2x+4)-(x+3)(x-3)+(5x-2)(3x+4)
b) (4x-1)x(3x+1)-5x^2x(x-3)-(x-4)x(x-5)-7(x^3-2x^2+x-1)
c) (5x-7)(x-9)-(3-x)(2-5x)-2x(x-4)
d)(5x-4)(x+5)-(x+1)(x^2-6)-5x+19
e)(9x^2-5)(x-3)-3x^2(3x+9)-(x-5)(x+4)-9x^3
g) (x-1)^2 - (x+2)^2
Thanks mn nhiều ạ
giải giúp mk vs :
a) 6x^2-5x+3=2x-3x(2-x)
b) 25x^2-9=(5x+3)(2x+1)
c) (3x-4)^2-4(x+1)^2=0
d) 3x^2-7x+4=0
e) 2x-5+3x=3x+6
tìm x bik
a) (8x-3)(3x+2)- (4x+7)(x+4)=(2x+1)(5x-1)
b) (8-5x)(x+2) + 4(x-2)(x+1)+2(x-2)(x+2) = 0
c) 4 ( x-1)(x+5) - (x+2)(x+5) = 3(x-1)(x+2).
giúp vs ạ
