Question

b/ 2x= 3y= 5z và x.y.z = 36

cứu tui mng ơi

Answer 1

Ta có :

2x=3y = \(\dfrac{x}{3}\) = \(\dfrac{y}{2}\) = \(\dfrac{x}{15}\) = \(\dfrac{y}{10}\)

3y=5z = \(\dfrac{y}{5}\) = \(\dfrac{z}{3}\) = \(\dfrac{y}{10}\) = \(\dfrac{z}{6}\)

=> \(\dfrac{x}{15}\) = \(\dfrac{y}{10}\) = \(\dfrac{z}{6}\) = \(\dfrac{x.y.z}{15.10.6}\) = \(\dfrac{36}{900}\)= \(\dfrac{1}{25}\)

=> x= \(\dfrac{1}{25}\) . 15 =\(\dfrac{3}{5}\)

y=\(\dfrac{1}{25}\) . 10 = \(\dfrac{2}{5}\)

z=\(\dfrac{1}{25}\).6 = \(\dfrac{6}{25}\)

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