Question

b) ( 1999×1998+1998×1997)×(11×9-900×0,1)

Answer 1

\(\left(1999\times1998+1998\times1997\right)\times\left(11\times9-900\times0,1\right)\)

\(=\left[1998\times\left(1999+1997\right)\right]\times\left[9\times\left(11-10\right)\right]\)

\(=1998\times3996\times9\)

Đáp số to nên k tính hết ra đc.

Answer 2

$\left(1999\times 1998+1998\times 1997\right)\times \left(11\times 9-900\times 0,1\right)$

$=\left[1998\times \left(1999+1997\right)\right]\times \left[9\times \left(11-10\right)\right]$

$=1998\times 3996\times 9$

= 71.856.072