Question

a)(x+2)-(x+1)^2=0

b)1-(x-2)^2=0

c)x+5-x^2+25=0

Answer 1

\(1-\left(x-2\right)^2=0\)

\(\Leftrightarrow1=\left(x-2\right)^2\)

\(\Leftrightarrow x-2=1\)

\(\Leftrightarrow x=3\)

Answer 2

\(\left(x+2\right)-\left(x+1\right)^2=0\)

\(\Leftrightarrow x+2=\left(x+1\right)^2\)

tự giải tiếp...............................

Answer 3

\(x+5-x^2+25=0\)

\(x+5-x^2=0-25\)

\(x+5-x^2=-25\)

\(x-x^2=-25-5\)

\(x-x^2=-30\)

\(x\left(1-x\right)=-30\)

\(x=-5\)

Answer 4

sai luôn rồi

1=(x-2)^2

x-2=1

hoặc x-2=-1

nha box- toán

Answer 5

Boss NCTK ( Box - Toán ): không biết làm thì thôi chứ đừng nói tự giải tiếp nhé Nguyễn Châu Tuấn Kiệt

\(\left(x+2\right)-\left(x+1\right)^2=0\)

\(\Leftrightarrow\left(x+2\right)-x^2-2x-1=0\)

\(\Leftrightarrow-x^2-x+1=0\)

\(\Leftrightarrow x^2+x-1=0\)

\(\Leftrightarrow x^2+x+\frac{1}{4}-\frac{5}{4}=0\)

\(\Leftrightarrow\left(x+\frac{1}{2}\right)^2-\left(\frac{\sqrt{5}}{2}\right)^2=0\)

\(\Leftrightarrow\left(x+\frac{1-\sqrt{5}}{2}\right)\left(x+\frac{1+\sqrt{5}}{2}\right)=0\)

Tự làm nốt...

P/S: Theo mình, đề là \(\left(x+2\right)^2-\left(x+1\right)^2=0\)thì đúng ( dễ làm ) hơn