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Question

A.x+17=3⁵:3²
B.5.6 mũ x+1-2.3²=12
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chuche · Accepted Answer

`x+17=3^5:3^2``=>x+17=3^3``=>x+17=27``=>x=27-17``=>x=10`__`5.6^(x+1)-2.3^2=12``=>5.6^(x+1)-2.9=12``=>5.6^(x+1)-18=12``=>5.6^(x+1)=12+18=30``=>6^(x+1)=30:5``=>6^(x+1)=6``=>x+1=1``=>x=0`Câu trả lời: `x+17=3^5:3^2``=>x+17=3^3``=>x+17=27``=>x=27-17``=>x=10`__`5.6^(x+1)-2.3^2=12``=>5.6^(x+1)-2.9=12``=>5.6^(x+1)-18=12``=>5.6^(x+1)=12+18=30``=>6^(x+1)=30:5``=>6^(x+1)=6``=>x+1=1``=>x=0`

Mẫn Nhi · Answer

A. $\text{x + 17 = 3⁵ : 3²}$    $x+17=3^{5-2}$    $x+17=3^3$     $x+17=27$     $x=27-17$     $x=10$B.$5\cdot6^{x+1}-2\cdot3^2=12$  $5\cdot6^{x+1}-2\cdot9=12$ $5\cdot6^{x+1}-18=12$$5\cdot6^{x+1}=18+12$$5\cdot6^{x+1}=30$$6^{x+1}=\dfrac{30}{5}$$6^{x+1}=6$$x+1=1$ $x=0$$x+1=1$ vì $6=6^1$     Câu trả lời: A. $\text{x + 17 = 3⁵ : 3²}$    $x+17=3^{5-2}$    $x+17=3^3$     $x+17=27$     $x=27-17$     $x=10$B.$5\cdot6^{x+1}-2\cdot3^2=12$  $5\cdot6^{x+1}-2\cdot9=12$ $5\cdot6^{x+1}-18=12$$5\cdot6^{x+1}=18+12$$5\cdot6^{x+1}=30$$6^{x+1}=\dfrac{30}{5}$$6^{x+1}=6$$x+1=1$ $x=0$$x+1=1$ vì $6=6^1$

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