a) \(x-\frac{1}{4}-\frac{5}{3}\text{x}\frac{1}{2}=x-\frac{1}{4}-\frac{5\text{x}1}{3\text{x}2}\)
\(\Rightarrow x-\frac{1}{4}-\frac{5}{6}=x-\left(\frac{1}{4}+\frac{5}{6}\right)\)
\(\Rightarrow x-\left(\frac{3}{12}+\frac{10}{12}\right)=x-\frac{13}{12}\)
b) \(x:\frac{2}{3}-\frac{1}{2}+\frac{3}{4}=\frac{3}{2}x-\frac{1}{2}+\frac{3}{4}\)
\(\Rightarrow\frac{3x}{2}-\frac{1}{2}+\frac{3}{4}=\frac{3x-1}{2}+\frac{3}{4}\)
\(\Rightarrow\frac{\left(3x-1\right)\text{x}2}{4}+\frac{3}{4}=\frac{\left(3x-1\right)\text{x}2+3}{4}\)
\(\Rightarrow\frac{6x-2+3}{4}=\frac{6x+1}{4}\)
mik đng cần siên gấp luôn nên giúp mik
