Question

a)\(\sqrt{12}+\sqrt{27}-\sqrt{3}\)

b)\(\sqrt{0,16}-\sqrt{0,25}\)

Answer 1

\(\sqrt{12}+\sqrt{27}-\sqrt{3}=\sqrt{2.2.3}+\sqrt{3.3.3}-\sqrt{3}\)

\(=2\sqrt{3}+3\sqrt{3}-\sqrt{3}=4\sqrt{3}\)

Answer 2

\(\sqrt{0,16}-\sqrt{0,25}=0,4-0,5=\left(-0,1\right)\)

Answer 3

\(a.\sqrt{12}+\sqrt{27}-\sqrt{3}\)

\(=\sqrt{4\times3}+\sqrt{9\times3}-\sqrt{3}\)

\(=\sqrt{4}\times\sqrt{3}+\sqrt{9}\times\sqrt{3}-\sqrt{3}\)

\(=2\times\sqrt{3}+3\times\sqrt{3}-1\times\sqrt{3}\)

\(=\sqrt{3}\left(2+3-1\right)\)

\(=4\sqrt{3}\)

\(b.\sqrt{0,16}-\sqrt{0,25}\)

\(=0,4-0,5\)

\(=-0,1\)

Answer 4

   \(\rightarrow\)  Thank you   \(\leftarrow\)

Thank you every body were help me!

Lady Vu