Question

\(a,\left(x-2\right)^2=1\)

Answer 1

`(x-2)^2=1`

`(x-2)^2=`\(\left(\pm1\right)^2\)

`@TH1:`

`x-2=1`

`x=1+2`

`x=3`

`@TH2:`

`x-2=-1`

`x=-1+2`

`x=1`

Vậy `x = {3;1}`

Answer 2

\(TH1\left(x-2\right)^2=1^2\\ x-2=1\\ x=3\\ TH2\left(x-2\right)^2=\left(-1\right)^2\\ x-2=-1\\ x=1\)

Answer 3

`(x-2)^2=1`

`(x-2)^2=1^2` hoặc `(x-2)^2=(-1)^2`

`x-2=1`   hoặc `x-2=-1`

`x=3`    hoặc `x=1`

Answer 4

\(\left(x-2\right)^2=1\)

\(\Rightarrow\left[{}\begin{matrix}x-2=1\\x-2=-1\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=3\\x=1\end{matrix}\right.\)

Answer 5

`a,`

`(x−2)^2=1`

`=>(x-2)^2=1^2`

`TH1`

`x-2=1`

`=>x=1+2`

`=>x=3`

`TH2`

`x-2=-1`

`=>x=-1+2`

`=>x=1`

Answer 6

a) \(\left(x-2\right)^2=1\)

\(\left(x-2\right)^2=1^2\)

\(\Rightarrow\left[{}\begin{matrix}x-2=1\\x-2=-1\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=3\\x=1\end{matrix}\right.\)