Question

a,\(\left\{\frac{2}{3}\right\}^3-\left\{\frac{3}{4}\right\}^2.\left\{-1\right\}^5\)

b,\(12:\left\{\frac{3}{4}-\frac{5}{6}\right\}^2\)

c,\(\frac{7}{22}:\frac{3}{11}+\frac{7}{22}:\frac{4}{11}\)

d,\(\frac{12}{35}.\left\{\frac{7}{4}+\frac{13}{4}\right\}-\frac{1}{3}\)

Answer 1

a. \(\left(\frac{2}{3}\right)^3-\left(\frac{3}{4}\right)^2.\left(-1\right)^5=\frac{8}{27}-\frac{9}{16}.\left(-1\right)=\frac{8}{27}+\frac{9}{16}=\frac{371}{432}\)

b. \(12:\left(\frac{3}{4}-\frac{5}{6}\right)^2=12:\left(-\frac{1}{12}\right)^2=12:\frac{1}{144}=12.144=1728\)

c. \(\frac{7}{22}:\frac{3}{11}+\frac{7}{22}:\frac{4}{11}=\frac{7}{22}.\frac{11}{3}+\frac{7}{22}.\frac{11}{4}=\frac{7}{22}\left(\frac{11}{3}+\frac{11}{4}\right)\)

\(=\frac{7}{22}.\frac{77}{12}=\frac{49}{24}\)

d. \(\frac{12}{35}\left(\frac{7}{4}+\frac{13}{4}\right)-\frac{1}{3}=\frac{12}{35}.5-\frac{1}{3}=\frac{12}{7}-\frac{1}{3}=\frac{29}{21}\)