ta có \(3x^2=2x\)
\(3x^2-2x=0\)
\(x\left(3x-2\right)=0\)
\(=>\orbr{\begin{cases}x=0\\3x-2=0=>x=\frac{2}{3}\end{cases}}\)
\(3x^2=2x\)
\(3x^2-2x=0\)
\(x\left(3x-2\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x=0\\3x-2=0\end{cases}}\)\(\Leftrightarrow\orbr{\begin{cases}x=0\\x=\frac{2}{3}\end{cases}}\)
vậy x=0 hoặc x=\(\frac{2}{3}\)