\(-5x^2+20x-49=-5\left(x^2-4x+\frac{49}{5}\right)=-5\left(x^2-2.x.2+4+\frac{29}{5}\right)\)
\(=-5\left(x-2\right)^2-\frac{29}{5}=\frac{-29}{5}-5\left(x-2\right)^2\)
Vì \(\left(x-2\right)^2\ge0\Rightarrow5\left(x-2\right)^2\ge0\)
Suy ra: \(\frac{-29}{5}-5\left(x-2\right)^2\le\frac{-29}{5}< 0\)
Vậy ...........