\(\Rightarrow3^{x-1}=\frac{1}{243}x3\)
\(\Rightarrow3^{x-1}=\frac{1}{81}\)
Ko có x thỏa mãn
\(3^{x-1}:3=\frac{1}{243}\)
\(3^{x-2}=3^{-5}\)
\(\Rightarrow x-2=-5\)
\(x=-3\)
Vậy x= -3
3x-1 : 3 = \(\frac{1}{243}\)
=> 3x-1 = \(\frac{1}{81}\)
mà 81 = 92
=> 3x-1 = \(\frac{1}{\left(9^2\right)}\)
=> x = ..........
rắc rối chắc sai quá !! 564575475675687857556686586444456
\(3^{x-1}:3=\frac{1}{243}\)
\(\Leftrightarrow3^{x-1}:3=\frac{1}{3^5}\)
\(\Leftrightarrow3^{x-1}:3=3^{-5}\)
\(\Leftrightarrow3^{x-1}=3^{-5}.3=3^{-4}\)
\(\Leftrightarrow x-1=-4\)
\(\Leftrightarrow x=-4+1=-3\)
Vậy \(x=-3\)