\(2^x+2^{x+1}=96\)
\(\Rightarrow2^x\left(1+2\right)=96\)
\(\Rightarrow2^x.3=96\)
\(2^x=96:3\)
\(2^x=32\)
\(\Rightarrow2^x=2^5\)
\(x=5\)
a)2x+2x+1=96
2x+2x.2=96
2x.(1+2)=96
2x=32=25
Vậy x=5
b)4x+2 × 5 × 4x = 1280
4x.42 × 4x = 256
4x.(42+1)=256
4x.17=256
4x=\(\frac{256}{17}\)