Question

Ai bít làm dạng này ko chỉ em với

Answer 1

a, \(sinx=1\Leftrightarrow x=\dfrac{\pi}{2}+k2\pi\)

b, \(sinx=\dfrac{\sqrt{3}}{2}\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{\pi}{3}+k2\pi\\x=\pi-\dfrac{\pi}{3}+k2\pi\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{\pi}{3}+k2\pi\\x=\dfrac{2\pi}{3}+k2\pi\end{matrix}\right.\)

c, \(sinx=\dfrac{1}{6}\Leftrightarrow\left[{}\begin{matrix}x=arcsin\dfrac{1}{6}+k2\pi\\x=\pi-arcsin\dfrac{1}{6}+k2\pi\end{matrix}\right.\)