a) \(\frac{x-3}{5}=\frac{4}{9}\)
=> ( x - 3) . 9 = 20
=> 9x - 27 = 20
=> 9x = 47
=> x = \(\frac{47}{9}\)
b) \(\left(x-\frac{1}{4}\right)^2:3^2=81\)
\(\Rightarrow\left(x-\frac{1}{3}\right)^2:9=81\)
\(\Rightarrow\left(x-\frac{1}{4}\right)^2=729\)
\(\Rightarrow x-\frac{1}{4}=27\) hoặc \(x-\frac{1}{4}=-27\)
+) \(x-\frac{1}{4}=27\Rightarrow x=\frac{109}{4}\)
+) \(x-\frac{1}{4}=-27\Rightarrow x=\frac{-107}{4}\)