Các câu hỏi tương tự
Cho A = \(\left(\frac{x-\sqrt{x}+7}{x-4}+\frac{1}{\sqrt{x}-2}\right):\left(\frac{\sqrt{x}+2}{\sqrt{x}-2}-\frac{\sqrt{x}-2}{\sqrt{x}+2}-\frac{2\sqrt{x}}{x-4}\right)\)
a) Rut gon A
b) So sanh A voi \(\frac{1}{A}\)
Rut gon bieu thuc
M=\(\frac{2\sqrt{x}-3}{\sqrt{x}-4}-\frac{\sqrt{x}+2}{\sqrt{x}+1}-\)\(\frac{2-3\sqrt{x}}{x-3\sqrt{x}-4}\)
\(P=\frac{\sqrt{x}+1}{\sqrt{x}-2}+\frac{2\sqrt{x}}{\sqrt{x}+2}+\frac{2+5\sqrt{x}}{4-x}\)
rut gon
Rut gon bieu thuc
\(A=\sqrt{x-\frac{1}{2}+\sqrt{x-\frac{1}{2}+\sqrt{x+\sqrt{x-\frac{1}{4}}}}}\)
\(p=\frac{\sqrt{x}+1}{\sqrt{x}-2}+\frac{2\sqrt{x}}{\sqrt{x}+2}+\frac{2+5\sqrt{x}}{4-x}\)
a,rut gon
b,tim x de p duong
rut gon bieu thuc A=\(\left(\frac{\sqrt{x}}{x-4}+\frac{2}{2-\sqrt{x}}+\frac{1}{\sqrt{x}+2}\right):\left(\sqrt{x}-2+\frac{10-x}{\sqrt{x}+2}\right)\) tìm giá trị của x để A>0
a\Rut gon bieu thuc
b/Tim gia tri nho nhat cua 4A
A=\(\frac{5\sqrt{x}+4}{x+\sqrt{x}-2}+\frac{\sqrt{x}-1}{\sqrt{x}+2}-\)\(\frac{\sqrt{x}+2}{\sqrt{x}-1}\)
Rut gon bieu thuc : Q \(=\frac{4\sqrt{x}}{9x-1}+\frac{1-\sqrt{x}}{1-3\sqrt{x}}\)
P=\(\frac{3\left(x+\sqrt{x}-3\right)}{x+\sqrt{x}-2}+\frac{\sqrt{x}+3}{\sqrt{x}+2}+\frac{\sqrt{x}-2}{1-\sqrt{x}}\\ \)
a, rut gon
b, tim x de P<\(\frac{15}{4}\)
c, tim gia tri lon nhat cua P