Question

\(A=\frac{a^3+2a^2-1}{a^3+2a^2+2a+1}\)

a)Rút gọn biểu thức

Answer 1

\(A=\frac{a^3+2a^2-1}{a^3+2a^2+2a+1}=\frac{a^3+a^2+a^2-1}{a^3+a^2+a^2+a+a+1}=\frac{\left(a^3+a^2\right)+\left(a^2-1\right)}{\left(a^3+a^2\right)+\left(a^2+a\right)+\left(a+1\right)}\)

\(A=\frac{a^2\left(a+1\right)+\left(a-1\right)\left(a+1\right)}{a^2\left(a+1\right)+a\left(a+1\right)+\left(a+1\right)}=\frac{\left(a+1\right).\left(a^2+a-1\right)}{\left(a+1\right).\left(a^2+a+1\right)}=\frac{a^2+a-1}{a^2+a+1}\)

Vậy \(A=\frac{a^2+a-1}{a^2+a+1}\)

Answer 2

1 8892219

Answer 3

A=12213213313