c/ \(\frac{2x-5}{7}=\frac{5-2x}{5}\)
=> 5 (2x - 5) = 7 (5 - 2x)
=> 10x - 25 = 35 - 14x
=> 10x + 14x = 35 + 25
=> 24x = 60
=> x = 2,5
\(a)\) \(\frac{8-11x}{4}=13\)
\(\Leftrightarrow\)\(8-11x=13.4\)
\(\Leftrightarrow\)\(8-11x=52\)
\(\Leftrightarrow\)\(11x=8-52\)
\(\Leftrightarrow\)\(11x=-44\)
\(\Leftrightarrow\)\(x=\frac{-44}{11}\)
\(\Leftrightarrow\)\(-4\)
Vậy \(x=-4\)
chưa ai làm câu thứ 2 sao :))
b) \(\frac{3x-4}{7}=2\)
\(\Leftrightarrow\)\(3x-4=2.7\)
\(\Leftrightarrow\)\(3x-4=14\)
\(\Leftrightarrow\)\(3x=18\Leftrightarrow x=\frac{18}{3}=6\)
Nhân chéo tích lên là được nhé
\(a\frac{8-11x}{4}=13\)
\(\Leftrightarrow8-11x=52\)
\(\Leftrightarrow-11x=44\)
\(\Leftrightarrow x=-4\)
\(b.\frac{3x-4}{7}=2\)
\(3x-4=14\)
\(\Leftrightarrow3x=18\)
\(\Leftrightarrow x=6\)
c.\(\frac{2x-5}{7}=\frac{5-2x}{5}\)
\(\Leftrightarrow5\left(2x-5\right)=7\left(5-2x\right)\)
\(\Leftrightarrow10x-25=35-14x\)
\(\Leftrightarrow10x+14x=25+35\)
\(\Leftrightarrow24x=60\)
\(\Leftrightarrow x=2,5\)
xl mik chưa kết luận nghiệm
\(a.\)vậy\(S=\left\{-4\right\}\)
B.Vậy \(S=\left\{6\right\}\)
c.vậy \(S=\left\{2,5\right\}\)