Question

A=\(\frac{7}{19}x\frac{8}{11}x\frac{7}{19}:\frac{3}{11}+\frac{12}{19}\)

Answer 1

\(A=\frac{7}{19}.\frac{8}{11}.\frac{7}{19}:\frac{3}{11}+\frac{12}{19}\)

\(A=\left(\frac{7}{19}\right)^2.\frac{8}{11}.\frac{11}{3}+\frac{12}{19}\)

\(\Rightarrow A=\left(\frac{7}{19}\right)^2.\frac{8}{3}+\frac{12}{19}\)

\(\Rightarrow A=\frac{392}{1083}+\frac{12}{19}\)

\(\Rightarrow A=\frac{1076}{1083}\)

Answer 2

ban sai roi nha

Answer 3

Ta có 27^5=3^3^5=3^15
243^3=3^5^3=3^15
Vậy A=B
2^300=2^(3.100)=2^3^100=8^100
3^200=3^(2.100)=3^2^100=9^100
Vậy A<B