Question

\(A=\frac{5x+3y}{6x-7y}\) biết \(\frac{x}{y}=\frac{2}{3}\)

Answer 1

Ta có :  \(\frac{x}{y}=\frac{2}{3}\Rightarrow x=\frac{2}{3}y\)

Thay \(x=\frac{2}{3}y\)vào A , ta được : 

\(A=\frac{5.\frac{2}{3}y+3y}{6.\frac{2}{3}y-7y}\)

\(\Rightarrow A=\frac{\frac{10}{3}y+3y}{4y-7y}\)

\(\Rightarrow A=\frac{\left(\frac{10}{3}+3\right)y}{-3y}\)

\(\Rightarrow A=\frac{\frac{19}{3}y}{-3y}\)

\(\Rightarrow A=\frac{\frac{19}{3}}{-3}\)

\(\Rightarrow A=\frac{19}{3}.-\frac{1}{3}\)

\(\Rightarrow A=-\frac{19}{9}\)

Vậy \(A=-\frac{19}{9}\)

Answer 2

Trả lừoi

A=-19/9

nha 

hok tốt

Answer 3

Natsu làm chuẩn đấy.

Answer 4

\(\frac{x}{y}\)= \(\frac{2}{3}\)=>\(\frac{x}{2}\)=

Answer 5

\(\frac{x}{2}\)\(=\frac{y}{3}\)=>\(\frac{5x}{10}\)\(=\frac{3y}{9}\)\(=\frac{5x+3y}{10+9}\)\(=\frac{5x+3y}{19}\)\(=\frac{6x}{12}\)\(=\frac{7y}{21}\)\(=\frac{6x-7y}{12-21}\)\(=\frac{6x-7y}{-9}\)

\(=>\frac{5x+3y}{6x-7y}\)\(=\frac{-19}{9}\)

\(#Hoktot~\)