\(\frac{2^3.2^5.4^2}{2^9}=\frac{2^8.2^4}{2^9}=\frac{2^{12}}{2^9}=2^3=8\)
~Hok tốt ~
Tham khảo:
\(\frac{2^3.2^5.4^2}{2^9}=\frac{2^8.2^4}{2^9}=\frac{2^{12}}{2^9}=2^3=8\)
Ok.
Tính:
\(a.\frac{1}{99}-\frac{1}{99.98}-...-\frac{1}{3.2}-\frac{1}{2.1}\)
\(b.\frac{2}{100.99}-\frac{2}{99.98}-...-\frac{2}{3.2}-\frac{2}{2.1}\)
rút gọn:
a)\(\frac{4^3.1^5}{9^2.8^2}\) b)\(\frac{25^2.2^2.4^1}{3^3.2^3.224}\) c)\(\frac{25^3.5^6.5^2}{9^4.10^2}\)
\(\frac{5.4^{15}.9^9-4.\left(-3\right)^{20}.8^9}{5.2^9.6^{19}-7.\left(-2\right)^{29}.27^6}\)
Tìm x:
2x+2 - 3.2x =16
\(\left(\frac{1}{5}-\frac{3}{2}x\right)^2=\frac{9}{4}\)
Tính nhanh
a) \(A=\frac{1}{3}-\frac{3}{4}-\left(\frac{3}{5}\right)+\frac{1}{72}-\frac{2}{9}-\frac{1}{36}+\frac{1}{15}\)
b) \(B=\frac{1}{5}-\frac{3}{7}+\frac{5}{9}-\frac{2}{11}+\frac{7}{13}-\frac{9}{16}-\frac{7}{13}+\frac{2}{11}-\frac{5}{9}+\frac{3}{7}-\frac{1}{5}\)
c)\(C=\frac{1}{100}-\frac{1}{100.99}-\frac{1}{99.98}-\frac{1}{98.97}-...-\frac{1}{3.2}-\frac{1}{2.1}\)
Thực hiện phép tính:
a) \(\frac{-5}{9}.\left(\frac{3}{10}-\frac{2}{5}\right)\)
b) \(2^8:2^5+3^3.2-12\)
c) \(\frac{1}{2}\sqrt{64}-\sqrt{\frac{4}{25}}+1^{2012}\)
d) \(\left(-3\right)^2+\sqrt{\frac{16}{25}}-\sqrt{9}+\frac{\sqrt{81}}{3}\)
Hãy giúp mình câu này: 10.8x + 3.2 = 9.6x - 5.4
Giúp mình với nhé:
Tính:
a)\(\left(\frac{1}{2^2-1}\right).\left(\frac{1}{3^2-1}\right).\left(\frac{1}{4^2-1}\right)...\left(\frac{1}{98^2-1}\right).\left(\frac{1}{99^2-1}\right)\)
b)\(4\frac{1}{2}-\frac{15}{10.9}-\frac{15}{9\cdot8}-\frac{15}{3.2}-\frac{15}{2.1}\)
Giúp mik 2 bài này với
A = \(\frac{1}{5}-\frac{3}{7}+\frac{5}{9}-\frac{2}{11}+\frac{7}{13}-\frac{9}{16}-\frac{7}{13}+\frac{2}{11}-\frac{5}{9}+\frac{3}{7}-\frac{1}{5}\)
B = \(\frac{1}{100}-\frac{1}{100.99}-\frac{1}{99.98}-\frac{1}{98.97}-...-\frac{1}{3.2}-\frac{1}{2.1}\)
Cố gắng giúp mik giải 1 cách chi tiết nhé
