Question

\(A=\frac{1999}{2000}+\frac{2000}{2001}vàB=\frac{1999+2000}{2000+2001}\)

 

Answer 1

Ta có :

\(B=\frac{1999+2000}{2000+2001}=\frac{1999}{2000+2001}+\frac{2000}{2000+2001}\)

VẬY \(\frac{1999}{2000}>\frac{1999}{2000+2001}\)

        \(\frac{2000}{2001}>\frac{2000}{2000+2001}\)

\(\Rightarrow\frac{1999}{2000}+\frac{2000}{2001}>\frac{1999+2000}{2000+2001}\)

\(\Rightarrow A>B\)

CHÚC BN HỌC TỐT #

Answer 2

\(B=\frac{1999+2000}{2000+2001}=\frac{1999}{2000+2001}+\frac{2000}{2000+2001}\)

Ta có: \(\frac{1999}{2000}>\frac{1999}{2000+2001}\)

             \(\frac{2000}{2001}>\frac{2000}{2000+2001}\)

\(\Rightarrow A>B\)

Answer 3

\(A=\frac{1999}{2000}+\frac{2000}{2001}v\text{à}B=\frac{1999+2000}{2000+2001}=\frac{1999}{2000+2001}+\frac{2000}{2000+2001}\)

\(V\text{ì}\frac{1999}{2000}>\frac{1999}{2000+2001};\frac{2000}{2001}>\frac{2000}{2000+2001}\)

Từ đó suy ra A>B