\(A=\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}=\frac{11.3^{29}-\left(3^2\right)^{15}}{2^2.3^{28}}\)
\(A=\frac{11.3^{29}-3^{30}}{4.3^{28}}\)
\(A=\frac{3^{29}.\left(11-3\right)}{4.3^{28}}\)
\(A=\frac{3^{29}.8}{4.3^{28}}=3.2=6\)
\(\Rightarrow A=\frac{11.3^{29}-\left(3^2\right)^{15}}{2^2.3^{28}}\)
\(\Rightarrow A=\frac{11.3^{29}-3^{29}.3}{2^2.3^{28}}\)
\(\Rightarrow A=\frac{3^{29}.\left(11-3\right)}{2^2.3^{28}}\)
\(\Rightarrow A=\frac{3^{29}.2^3}{2^2.3^{28}}\)
\(\Rightarrow A=3.2\)
=> A=6
A = 11 . 329 - ( 32)15 /22 .328
A= 329. ( 11 - 3 )/ 22 . 328
A = 329 . 23 / 22 . 328
A = 3 .2
A = 6
Mong cac ban ung ho minh nha
ta có :11.3^22 .3^7--9^15
=11.3^29 - (3^2)^15
= 11.3^29-3^30
= 3^29. (11-3)
=3^29 .8
TA CÓ : (2.3^14) ^2
=2^2 .(3^14)^2
=2^2 . 3^28
Vậy A= 3^29.8/ 2^2. 3^28
cô giáo mk giảng bài này rồi đúng đó k mk nha
