Question

a,\(\frac{11}{125}\)- \(\frac{17}{18}\)-\(\frac{5}{7}\)+\(\frac{4}{9}\)+\(\frac{17}{14}\)

b,1-\(\frac{1}{2}\)+ 2 - \(\frac{2}{3}\)+ 3 - \(\frac{3}{4}\)+ 4 - \(\frac{1}{4}\)- 3 - \(\frac{1}{3}\)-2 - \(\frac{1}{2}\)- 1

Answer 1

\(\frac{11}{125}-\frac{17}{18}-\frac{5}{7}+\frac{4}{9}+\frac{17}{14}\)

\(=\left(-\frac{17}{18}+\frac{4}{9}\right)+\left(-\frac{5}{7}+\frac{17}{14}\right)+\frac{11}{125}\)

\(=-1+\frac{1}{2}+\frac{11}{125}\)

\(=-1+\frac{147}{125}\)

\(=\frac{22}{125}\)

Answer 2

2. \(1-\frac{1}{2}+2-\frac{2}{3}+3-\frac{3}{4}+4-\frac{1}{4}-3-\frac{1}{3}-2-\frac{1}{2}-1\)

\(=\left(1+2+3+4-3-2-1\right)\)\(+\left(-\frac{1}{2}-\frac{1}{2}\right)+\left(-\frac{2}{3}-\frac{1}{3}\right)+\left(-\frac{3}{4}-\frac{1}{4}\right)\)

\(=4-1-1-1\)

\(=1\)