a+0,b+0,0c+10a+b+0,c=21,12
11a+1,1b+0,11c=21,12
=>a=1
=>1,1b+0,11c=10,12
1,1b+0,11c=9,9+0,22
=>b=9;c=2
Vậy a=1;b=9;c=2
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a+0,b+0,0c+10a+b+0,c=21,12
11a+1,1b+0,11c=21,12
=>a=1
=>1,1b+0,11c=10,12
1,1b+0,11c=9,9+0,22
=>b=9;c=2
Vậy a=1;b=9;c=2
a,bc + ab,c= 21,12
a,bc +ab,c = 21,12
a,bc+ab,c=21,12
a,bc+ab,c=21,12
a,bc+ab,c= 21,12
a,bc+ab,c=21,12
a,bc+ab,c=21,12
a,bc+ab,c=21,12
a,bc+ab,c=21,12
a,bc+ab,c=21,12