a/
\(x\in\left\{3;4;...;10\right\}\)
b/
\(x\in\left\{1;2;3;4;5\right\}\)
c/
\(x\in\left\{3;4;5;6;7;8\right\}\)
a/
\(x\in\left\{3;4;...;10\right\}\)
b/
\(x\in\left\{1;2;3;4;5\right\}\)
c/
\(x\in\left\{3;4;5;6;7;8\right\}\)
choA= {xthuocN/x co 4c/s x chia 5 du 1 hoac 4 }
tinh tat ca cac fan tu cua a
tong tat ca cac phan tu so le cua tap hop B=(xthuocN|x<100;xchia het cho5
tim xthuocN biet
5x^2-5=2^3.3.10
4(x-2)^3+36:3^2=581
12.3^x+24=340
4.7^x-5^4=2^2.5.23
cho A={x thuoc Nsao cho x be hon hoac bang 4}
B={xthuoc N sao cho x be hon 7}
hay liet ke cac phan tu cua tap hop C sao cho C = A ^B
a, viet so lien truoc
100.,1000,599,700
x(xthuoc n), x-1,x+1
m-3,m-2,62
b ,viet so lien sau
1001,200,62
x(xthouc n),x-2,x+2
Cho A=(xthuoc N,x=7.9+3,q thuoc N, q be hon hoac= 150)
a. liet ke cac phan tu cua A
b.tinh tong cac phan tu cua A
cho tong
A=12+14+16+x voi xthuoc N.tim x de:
a) Achia het cho 2
b) Akhong chia het cho 2
tim xthuoc z biet
a) (x+5).(x-4)=0
b) (x-5)^6 = (x-5)^8
Tim x:
a, [x+1] + [x+2] + [x+3] + ... + [x+100] bang 206050
b, [1-3/10-x] : [19/20-1-2/5]
c, |2x-2| bang x+18
d, | |11-x| +9| - 7 bang 12