Question

`a)(6x-39):3=201`

`b)23+3x=5^6:5^3`

`c) 3x[8^2 - 2 . ( 2^5 - 1)] = 2022`

Answer 1

`a) ( 6x - 39 ) : 3 = 201`

`=> 6x - 39 = 201 xx 3`

`=> 6x - 39 = 6063`

`=> 6x = 6063 + 39`

`=> 6x = 6102`

`=> x = 6102 : 6`

`=> x = 1017`

`b) 23 + 3x = 5^6 : 5^3`

`=> 23 + 3x = 15625 : 125`

`=> 23 + 3x = 125`

`=> 3x = 125 - 23`

`=> 3x = 102`

`=> x = 102 : 3`

`=> x = 34`

`c) 3x[8^2 - 2 . ( 2^5 - 1)] = 2022`

`=> 3x[64 - 2 .(32 - 1)] = 2022`

`=> 3x[ 64 - 2 . 31]=2022`

=> 3x[64 - 62] = 2022`

`=> 3x . 2 = 2022`

`=> 6x = 2022`

`=> x = 2022 : 6`

`=> x = 337`