a)Ta có:5/3.x^2-1/2.x^2y
=(5/3-1/2).x^2y
= 7/6.x^2y(Bậc 3)
b)Ta có: 7/6.(-2)^2(-1)
= 7/6.4.(-1)
= 7/6.(-4)
=-28/6
a, - A=\(\dfrac{5}{3}\).x2.y-\(\dfrac{-1}{2}\).x2.y
=\(\dfrac{13}{6}\).x2.y
- Bậc= 3.
b, A=\(\dfrac{13}{6}\).(-2)2.(-1)
=\(\dfrac{13}{6}\).4.(-1)
=\(\dfrac{-26}{3}\)
bạn Tt_Cindy_tT làm sai rồi 5/3-1/2=7/6 chứ ko bằng 13/6