a)\(\dfrac{4}{1}+\dfrac{4}{7}=\dfrac{28}{7}+\dfrac{4}{7}=\dfrac{32}{7}\)
b)\(\dfrac{11}{3}+\dfrac{1}{1}=\dfrac{11}{3}+\dfrac{3}{3}=\dfrac{14}{3}\)
\(4+\dfrac{4}{7}=\dfrac{4}{1}+\dfrac{4}{7}=\dfrac{28}{7}+\dfrac{4}{7}=\dfrac{32}{7}\)
\(\dfrac{11}{3}+1=\dfrac{11}{3}+\dfrac{3}{3}=\dfrac{14}{3}\)