Question

a)\(3x\left(x-\hept{\begin{cases}2\\3\end{cases}}\right)=0\)\(\)tìm x      b)\(\frac{3}{4}+\frac{1}{4}:x=\frac{2}{5}\)  

Answer 1

\(a,3x\left(x-\frac{2}{3}\right)=0 \)
\(\)TH1:
3x=0
x=0:3
x=0
       TH2
\(x-\frac{2}{3}=0 \)
\(x=0+\frac{2}{3}=\frac{2}{3}\)
Vậy x={0;\(\frac{2}{3}\)}

Answer 2

34 +14 :x=25 

\(\frac{1}{4}:x=\frac{2}{5}-\frac{3}{4}\)

\(\frac{1}{4}:x=-\frac{7}{20}\)
\(x=\frac{1}{4}:-\frac{7}{20}\)
\(x=-\frac{20}{28}\)
\(x=-\frac{5}{7}\)